0=2y^2+8y+6

Solution for 0=2y^2+8y+6 equation:

0=2y^2+8y+6

We move all terms to the left:

0-(2y^2+8y+6)=0

We add all the numbers together, and all the variables

-(2y^2+8y+6)=0

We get rid of parentheses

-2y^2-8y-6=0

a = -2; b = -8; c = -6;
Δ = b2-4ac
Δ = -82-4·(-2)·(-6)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4}{2*-2}=\frac{4}{-4}
=-1
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4}{2*-2}=\frac{12}{-4}
=-3
$